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25x^2-8x-1.296=0
a = 25; b = -8; c = -1.296;
Δ = b2-4ac
Δ = -82-4·25·(-1.296)
Δ = 193.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-\sqrt{193.6}}{2*25}=\frac{8-\sqrt{193.6}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+\sqrt{193.6}}{2*25}=\frac{8+\sqrt{193.6}}{50} $
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